pablozw3-topics

  1. China’s Bold Move: Global AI Governance Proposal Explained

  2. India’s Cyber Commandos: Fighting AI-Driven Cybercrime

  3. Why 2025 is the ‘Gap Year’ for Artificial Intelligence

  4. How AI is Changing Global Power and Geopolitics

  5. AI Slowdown? The Truth Behind ‘Altman’s Pause’

  6. Ai-Da’s Masterpiece: The ‘Algorithm King’ Portrait of King Charles III

  7. Netflix’s Secret Weapon: Generative AI in VFX

  8. AI-Powered Smart Shopping Carts: The Future of Grocery Shopping is Here!

  9. AI Agents + IoT Data: How Smart Devices Are Learning to Think for Themselves

  10. Smart Agriculture Revolution: AI-Driven Date Sorting with 94% Accuracy

  11. Div-idy Explained: Build Websites & Games Using Just AI Prompts

  12. Artificial Tongue That Tastes and Learns: Mind-Blowing AI Innovation!

  13. The Future of AI Personal Assistants: From Siri to Super-Smart Companions

  14. AI-Powered Lie Detection: How Machines Are Learning to Spot Deception

  15. The Rise of Robo-Lawyers: Can AI Really Win Court Cases?


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Chapter no 1

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chapter 2

  1: Compute the Fourier coefficients for the function f(t) = t (0 ≤ t ≤ 1) Solution: To compute the Fourier series of the function f ( t ) = t f(t) = t f ( t ) = t on the interval 0 ≤ t ≤ 1 0 \leq t \leq 1 0 ≤ t ≤ 1 , we first need to express it as a periodic function of period 1. The Fourier series of a function f ( t ) f(t) f ( t ) on the interval [ 0 , 1 ] [0,1] [ 0 , 1 ] is given by: f ( t ) = a 0 + ∑ n = 1 ∞ ( a n cos ⁡ ( 2 π n t ) + b n sin ⁡ ( 2 π n t ) ) f(t) = a_0 + \sum_{n=1}^{\infty} \left( a_n \cos(2\pi nt) + b_n \sin(2\pi nt) \right) f ( t ) = a 0 ​ + n = 1 ∑ ∞ ​ ( a n ​ cos ( 2 πn t ) + b n ​ sin ( 2 πn t ) ) Where: a 0 = ∫ 0 1 f ( t )   d t = ∫ 0 1 t   d t = 1 2 a_0 = \int_0^1 f(t) \, dt = \int_0^1 t \, dt = \frac{1}{2} a 0 ​ = ∫ 0 1 ​ f ( t ) d t = ∫ 0 1 ​ t d t = 2 1 ​ a n = 2 ∫ 0 1 t cos ⁡ ( 2 π n t )   d t = 0 ( since this is an odd function about  t = 0.5 ) a_n = 2 \int_0^1 t \cos(2\pi nt) \, dt = 0 \quad (\text{since...
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chapter no 3

  1. The message is split into 10 frames, each with an 80% chance of arriving undamaged. What is the expected number of times the message must be sent to get the entire message through? Answer: Let the probability of a frame being transmitted successfully be 0.8, and the probability of a frame being damaged (and requiring retransmission) be 0.2. For one frame to arrive undamaged, the expected number of transmissions is the reciprocal of the probability of success: E [ transmissions per frame ] = 1 0.8 = 1.25 E[\text{transmissions per frame}] = \frac{1}{0.8} = 1.25 E [ transmissions per frame ] = 0.8 1 ​ = 1.25 Since there are 10 frames, the total expected number of transmissions is: E [ total transmissions ] = 10 × 1.25 = 12.5 E[\text{total transmissions}] = 10 \times 1.25 = 12.5 E [ total transmissions ] = 10 × 1.25 = 12.5 Thus, on average, the message will need to be sent  12.5 times  to get the entire message through. 2. Character Encoding...
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